//! This data structure is a generic tree which can contain any data. That data itself need to keep //! track of its own tree structure. //! //! This surely already exists. I am created it to test my own ability to do things in Rust. use std::{ cell::{Ref, RefCell}, collections::VecDeque, rc::Rc, }; #[derive(Clone, Debug)] pub enum Tree { Empty, Root(Node), } impl Default for Tree { fn default() -> Self { Tree::Empty } } impl Tree { pub fn new(value: T) -> (Tree, Node) { let node = Node::new(value); let tree = Tree::Root(node.clone()); (tree, node) } pub fn set_value(&mut self, value: T) -> Node { let node = Node::new(value); *self = Tree::Root(node.clone()); node } /// Use a breadth-first-search pattern to find a node, returning the node if found. pub fn find_bfs(&self, op: F) -> Option> where F: FnOnce(&T) -> bool + Copy, { let mut queue: VecDeque> = match self { Tree::Empty => VecDeque::new(), Tree::Root(node) => { let mut queue = VecDeque::new(); queue.push_back(node.clone()); queue } }; while let Some(node) = queue.pop_front() { if op(&node.value()) { return Some(node.clone()); } for child in node.children().iter() { queue.push_back(child.clone()) } } None } pub fn map(&self, op: F) -> Tree where F: FnOnce(&Node) -> Node + Copy, { match self { Tree::Empty => Tree::Empty, Tree::Root(root) => { let new_root = op(root); let mut queue: VecDeque<(Node, Node)> = root .children() .iter() .map(|child| (child.clone(), new_root.clone())) .collect(); while let Some((source, dest)) = queue.pop_front() { let res = op(&source); dest.add_child_node(res.clone()); for child in source.children().iter() { queue.push_back((child.clone(), res.clone())); } } Tree::Root(new_root) } } } } // By using the Rc container here, I'm able to make Node easily clonable while still // having the contents be shared. This means that I can change the tree structure without having to // make the visible objects mutable. // // This feels like cheating the type system. // // However, since I've moved the RefCell inside of the node, I can borrow the node multiple times // in a traversal function and I can make changes to nodes that I find. #[derive(Debug)] pub struct Node(Rc>>); impl Clone for Node { fn clone(&self) -> Self { Node(Rc::clone(&self.0)) } } #[derive(Debug)] struct Node_ { value: T, children: Vec>, } impl Node { pub fn new(value: T) -> Self { Self(Rc::new(RefCell::new(Node_ { value, children: vec![], }))) } /// Immutably retrieve the data in this node. pub fn value<'a>(&self) -> Ref { // Ref::map is not actually a member function. I don't know why this was done, other than // maybe to avoid conflicting with other `map` declarations. Why that is necessary when // Option::map exists as a member, I don't know. Ref::map(self.0.borrow(), |v| &v.value) } pub fn children<'a>(&self) -> Ref>> { Ref::map(self.0.borrow(), |v| &v.children) } pub fn add_child_node(&self, child: Node) { self.0.borrow_mut().children.push(child) } pub fn add_child_value(&self, value: T) -> Node { let node = Node::new(value); self.0.borrow_mut().children.push(node.clone()); node } } #[cfg(test)] mod tests { use super::*; #[test] fn can_find_node_in_tree() { let mut tree = Tree::default(); tree.set_value(15); assert!(tree.find_bfs(|val| *val == 15).is_some()); assert!(tree.find_bfs(|val| *val == 16).is_none()); let node = tree.find_bfs(|val| *val == 15).unwrap(); node.add_child_value(20); assert!(tree.find_bfs(|val| *val == 20).is_some()); } #[test] fn node_can_add_children() { let n = Node::new(15); n.add_child_value(20); assert_eq!(*n.value(), 15); // assert_eq!(n.children(), vec![Rc::new(RefCell::new(Node::new(20)))]); } #[test] fn it_can_map_one_tree_to_another() { let (tree, n) = Tree::new(15); let n = n.add_child_value(16); let _ = n.add_child_value(17); let tree2 = tree.map(|v| Node::new(v.value().to_string())); assert!(tree2.find_bfs(|val| *val == "15").is_some()); assert!(tree2.find_bfs(|val| *val == "16").is_some()); assert!(tree2.find_bfs(|val| *val == "17").is_some()); } }